Optimal. Leaf size=36 \[ \text{Unintegrable}\left (\frac{\sinh (c+d x) \cosh ^3(c+d x)}{(e+f x) (a+b \sinh (c+d x))},x\right ) \]
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Rubi [A] time = 0.0842915, antiderivative size = 0, normalized size of antiderivative = 0., number of steps used = 0, number of rules used = 0, integrand size = 0, \(\frac{\text{number of rules}}{\text{integrand size}}\) = 0., Rules used = {} \[ \int \frac{\cosh ^3(c+d x) \sinh (c+d x)}{(e+f x) (a+b \sinh (c+d x))} \, dx \]
Verification is Not applicable to the result.
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Rubi steps
\begin{align*} \int \frac{\cosh ^3(c+d x) \sinh (c+d x)}{(e+f x) (a+b \sinh (c+d x))} \, dx &=\int \frac{\cosh ^3(c+d x) \sinh (c+d x)}{(e+f x) (a+b \sinh (c+d x))} \, dx\\ \end{align*}
Mathematica [F] time = 180.001, size = 0, normalized size = 0. \[ \text{\$Aborted} \]
Verification is Not applicable to the result.
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Maple [A] time = 0.155, size = 0, normalized size = 0. \begin{align*} \int{\frac{ \left ( \cosh \left ( dx+c \right ) \right ) ^{3}\sinh \left ( dx+c \right ) }{ \left ( fx+e \right ) \left ( a+b\sinh \left ( dx+c \right ) \right ) }}\, dx \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Maxima [A] time = 0., size = 0, normalized size = 0. \begin{align*} -\frac{e^{\left (-3 \, c + \frac{3 \, d e}{f}\right )} E_{1}\left (\frac{3 \,{\left (f x + e\right )} d}{f}\right )}{8 \, b f} - \frac{a e^{\left (-2 \, c + \frac{2 \, d e}{f}\right )} E_{1}\left (\frac{2 \,{\left (f x + e\right )} d}{f}\right )}{4 \, b^{2} f} + \frac{a e^{\left (2 \, c - \frac{2 \, d e}{f}\right )} E_{1}\left (-\frac{2 \,{\left (f x + e\right )} d}{f}\right )}{4 \, b^{2} f} - \frac{e^{\left (3 \, c - \frac{3 \, d e}{f}\right )} E_{1}\left (-\frac{3 \,{\left (f x + e\right )} d}{f}\right )}{8 \, b f} - \frac{{\left (4 \, a^{2} + 3 \, b^{2}\right )} e^{\left (-c + \frac{d e}{f}\right )} E_{1}\left (\frac{{\left (f x + e\right )} d}{f}\right )}{8 \, b^{3} f} - \frac{{\left (4 \, a^{2} e^{c} + 3 \, b^{2} e^{c}\right )} e^{\left (-\frac{d e}{f}\right )} E_{1}\left (-\frac{{\left (f x + e\right )} d}{f}\right )}{8 \, b^{3} f} - \frac{{\left (a^{3} + a b^{2}\right )} \log \left (f x + e\right )}{b^{4} f} + \frac{1}{16} \, \int \frac{32 \,{\left (a^{3} b + a b^{3} -{\left (a^{4} e^{c} + a^{2} b^{2} e^{c}\right )} e^{\left (d x\right )}\right )}}{b^{5} f x + b^{5} e -{\left (b^{5} f x e^{\left (2 \, c\right )} + b^{5} e e^{\left (2 \, c\right )}\right )} e^{\left (2 \, d x\right )} - 2 \,{\left (a b^{4} f x e^{c} + a b^{4} e e^{c}\right )} e^{\left (d x\right )}}\,{d x} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Fricas [A] time = 0., size = 0, normalized size = 0. \begin{align*}{\rm integral}\left (\frac{\cosh \left (d x + c\right )^{3} \sinh \left (d x + c\right )}{a f x + a e +{\left (b f x + b e\right )} \sinh \left (d x + c\right )}, x\right ) \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Sympy [F(-1)] time = 0., size = 0, normalized size = 0. \begin{align*} \text{Timed out} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Giac [A] time = 0., size = 0, normalized size = 0. \begin{align*} \int \frac{\cosh \left (d x + c\right )^{3} \sinh \left (d x + c\right )}{{\left (f x + e\right )}{\left (b \sinh \left (d x + c\right ) + a\right )}}\,{d x} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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